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Question

If A, B and C denote the angles of a triangle, then Δ=∣ ∣1cosCcosBcosC1cosAcosBcosA1∣ ∣ is independent of

A
A
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B
B
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C
C
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D
none of these
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Solution

The correct options are
B B
C A
D C
Δ=∣ ∣1cosCcosBcosC1cosAcosBcosA1∣ ∣
Applying C1aC1+bC2+cC3
Δ=1a∣ ∣a+bcosC+ccosBcosCcosBacosCb+ccosA1cosAacosB+bcosAccosA1∣ ∣ ...... (By Projection Rule)

=1a∣ ∣0cosCcosB01cosA0cosA1∣ ∣=0
Therefore, independent of A, B and C.
Hence, options 'A', 'B' and 'C' are correct.

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