If $A, B$ and $C$ has $x, y$ and $z$ Rs. respectively, such that the sum of money of $A$ and $B$ is greater than the money what $C$ has. Then

x + y < z

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x + y > z

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x + z > y

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y + z < x

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Solution

The correct option is D $x + y > z$
It is given that the sum of money of $A$ and $B$ is greater than the money what $C$ has, where $A$ has $x$ Rs., $B$ has $y$ Rs. and $C$ has $z$ Rs.

Sum of money of $A$ and $B$ is $x + y$ and if it is greater than the money of $C C$ then it means $x + y > z$ because $C$ has $z$ Rs.

Hence, the required answer is $x + y > z$ .

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