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Question

If a,b are positive real numbers such that the lines ax+9y=5 and 4x+by=3 are parallel, then the least possible value of a+b is

A
13
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B
12
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C
8
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D
6
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Solution

The correct option is C 12
Two lines are parallel when their slopes are equal.
Since a,b are positive real numbers, a4=9b
ab=36
Since 36 is the square of 6,a+b would be minimum when a and b are equal and in this case, 6 each.
Thus, a+b has the minimum value of 6+6=12

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