If a,b are roots of the equation 2x2−35x+2=0, then the value of (2a−35)3.(2b−35)3 is equal to-
A
10
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B
100
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C
64
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D
1
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Solution
The correct option is D64 f(x)=2x2−35x+2=0hasrootsa&bproductofroots=ab=22=1f(a)=02a2−35a+2=0(2a−35)=−2af(b)=02b2−35b+2=0(2b−35)=−2b(2a−35)3.(2b−35)3=(−2a)3(−2b)3=26(ab)3=261=64