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Question

If a,b are roots of the equation 2x2−35x+2=0, then the value of (2a−35)3.(2b−35)3 is equal to-

A
10
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B
100
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C
64
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D
1
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Solution

The correct option is D 64
f(x)=2x235x+2=0hasrootsa&bproductofroots=ab=22=1f(a)=02a235a+2=0(2a35)=2af(b)=02b235b+2=0(2b35)=2b(2a35)3.(2b35)3=(2a)3(2b)3=26(ab)3=261=64

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