Question

If $a$, $b$ are the integers other than zero, $m$ is an odd integer, the value of $(-a\times b{)}^m$ for $a=1$, $b=2$ and $m=3$ is

• A. $-8$
• B. $8$
• C. $16$
• D. $-16$

Answer 1

The correct option is A $-8$

Given expression: $(-a\times b{)}^m$, where $a=1$, $b=2$ and $m=3$
Substituting the values of $a$, $b$ and $m$, we get
$(-a\times b{)}^m=(-1\times 2{)}^3$
$=(-2{)}^3$
$=-2^3$
$\because$ As the base $(-2)$ is negative and the exponent $\left(3\right)$ is an odd number, negative sign will appear in the result.
$=-8$