Question

If(a+b) :(b+c) :(c+a) =6:7:8
And(a+b+c)=14 then what is the value of c.

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Answer 1

(a+b) :(b+c) :(c+a) =6:7:8
let
(a+b)=6k ; (b+c)=7k ;(c+a)=8k

Now, we get addition of LHS & RHS
2a+2b+2c=21k
2(a+b+c)=21k
2(14)=21k —————- [given - (a+b+c)=14]
28=21k
k=28/21
k=4/3 ———————(1)

Since,
a+b+c=14
c=14-(a+b)

we have,
a+b=6k
a+b=6(4/3) ——————-from 1
a+b=8

now,
c=14-(a+b)
c=14–8
c=6