Question

If (a+b):(b+c):(c+a)=6:7:8= and a+b+c = 14 find the value of b

• A. 7:5:9
• B. 5:7:9
• C. 9:5:7
• D. 9:7:5
• E. 7:9:5

Answer 1

The correct option is A

7:5:9

$a+b=6kb+c=7kc+a=8k2(a+b+c)=21ka+b+c=14k=\frac{28}{21}=\frac{4}{3}a=10.5k-(b+c)a=3.5k=\frac{7}{2}\times \frac{4}{3}=\frac{14}{3}b=\frac{10}{3}c=\frac{18}{3}a:b:c=7:5:9$