You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of n Terms

If a : b = ...

Question

If $a : b = b : c$ , then $a^{4} : b^{4}$ is equal to

a^{2} : b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} : c^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

c^{2} : a^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

b^{2} : a c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $a^{2} : c^{2}$
$\frac{a}{b} = \frac{b}{c}$
$b^{2} = a c \Rightarrow b^{4} = a^{2} c^{2}$
$∴ \frac{a^{4}}{b^{4}} = \frac{a^{4}}{a^{2} c^{2}} = \frac{a^{2}}{c^{2}}$ .

Suggest Corrections

Similar questions

△ A B C, a^{4} + b^{4} + c^{4} = 2 a^{2} b^{2} + b^{2} c^{2} + 2 c^{2} a^{2},

sin A

\frac{a^{2} + a b + b^{2}}{b^{2} + b c + c^{2}} = \frac{a}{c}

\frac{a^{4} + a^{2} b^{2} + b^{4}}{b^{4} + b^{2} c^{2} + c^{4}} = \frac{a^{2}}{c^{2}}

a + b + c = 0

\frac{1}{b^{2} + c^{2} - a^{2}} + \frac{1}{c^{2} + a^{2} - b^{2}} + \frac{1}{a^{2} + b^{2} - c^{2}}

△ = ⎡ ⎢ ⎣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ⎤ ⎥ ⎦

A_{2}, B_{2}, C_{2}

a_{2}, b_{2}, c_{2}

a_{1} A_{2} + b_{1} B_{2} + c_{1} C_{2}

\frac{a^{2} + b^{2} + c^{2}}{R^{2}}

8

a^{2} = b^{2} + c^{2}

b^{2} = c^{2} + a^{2}

c^{2} = a^{2} + b^{2}

Join BYJU'S Learning Program