If a/b=b/c, then find the value of 1/(b-c)+1/(c-a)

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a^{2} + b^{2} + c^{2} = 2 (b + c - 1)

a + b + c

\frac{1}{1 + a + b^{- 1}} + \frac{1}{1 + b + c^{- 1}} + \frac{1}{1 + c + a^{- 1}}

\frac{1}{1 + a + b^{- 1}} + \frac{1}{1 + b + c^{- 1}} + \frac{1}{1 + c + a^{- 1}}

If a = 1, b = -2 and c = 3 then find the value of a $^{2}$ +b $^{2}$ +c $^{2}$ +ab+bc+ca.

\frac{a^{2}}{7 b c}

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