Question

If $A,B$ be any two sets, then $(A\cup B{)}^{\prime }$ is equal to

• A. $A^{\prime }\cup B^{\prime }$
• B. $A^{\prime }\cap B^{\prime }$
• C. $A\cap B$
• D. $A\cup B$

Answer 1

The correct option is B $A^{\prime }\cap B^{\prime }$

It is De Morgan's law that $(A\cup B{)}^{\prime }=A^{\prime }\cap B^{\prime }$