If a,b belongs to C are the distinct roots of the equation x^2-x+1=0 then find a^101+b^107 is

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Solution

Since ω³ = 1

Dividing by multiples of ω³ we get ω^202 = ω
and ω^107 =ω²

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Similar questions

α, β \in C

x^{2} - x + 1 = 0

α^{101} + β^{107}

If the equation ax^2+bx+c=0 does not have 2 distinct real roots and a+c>b,

then prove that f(x)>=0,for all x belongs to real number.

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a

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