If a+b+c=0 and |a|=5,|b|=3 and |c|=7 then angle between a and b is
A
π2
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B
π3
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C
π4
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D
π6
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Solution
The correct option is Bπ3 Given, a+b+c=0 and |a|=5,|b|=3,|c|=7 ⇒a+b=c On squaring both sides, we get (a+b)2=(−c)2 ⇒|a+b|2=|c|2 ⇒|a|2+|b|2+2a⋅b=|c|2 (∵θ be the angle between a and b) ⇒(5)2+(3)2+2|a||b|cosθ=(7)2 ⇒25+9+2⋅5⋅3cosθ=49 ⇒30cosθ=15 ⇒cosθ=12=cos60∘ ⇒θ=π3