If a + b + c = 0, the correct statements for the equation ax2+bx+c=0 are
−(a+b)a is a root of the equation
If we substitute 1 in the equation, we get a+b+c = 0
⇒ 1 is a root of the equation ⇒ Option A
Let the other root be α
α x 1 = ca
α = ca ⇒OptionA,B
α + 1 = −ba
α = −ba−1
=−b−aa
=−(b+a)a⇒OptionC