Question

If a+b+c=0, The value of $\frac{a^2}{bc}+\frac{b^2}{ca}+\frac{c^2}{ab}$ is

• A. 1
• B. 0
• C. -1
• D. 3

Answer 1

The correct option is D 3

Since a+b+c=0
or a+b=-c
or (a+b)${}^3$ =-c${}^3$
or a${}^3$+b${}^3$+3ab(a+b)=-c${}^3$
or a${}^3$+b${}^3$+3ab(-c)=-c${}^3$
or a${}^3$+b${}^3$+c${}^3$=3abc
Dividing both the sides by abc we get
$\frac{a^2}{bc}+\frac{b^2}{ac}+\frac{c^2}{ab}=3$