If a + b + c = 0, then $a^{2}$ + $b^{2}$ + $c^{2}$ is -

–4(ab + bc + ca)

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–2(ab + bc + ca)

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2 – 2bc

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Solution

The correct option is B
–2(ab + bc + ca)

${(a + b + c)}^{2}$ = 0

$a^{2}$ + $b^{2}$ + $c^{2}$ +2(ab +bc + ca) = 0

$a^{2}$ + $b^{2}$ + $c^{2}$ = -2(ab +bc + ca)

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Similar questions

a + b + c = 0

\frac{a^{2}}{b c} + \frac{b^{2}}{c a} + \frac{c^{2}}{a b} =

a + b + c = 0

\frac{1}{b^{2} + c^{2} - a^{2}} + \frac{1}{c^{2} + a^{2} - b^{2}} + \frac{1}{a^{2} + b^{2} - c^{2}}

\frac{a^{2} + b^{2} + a b}{b^{2} + c^{2} + b c} + \frac{c^{2} + c a + a^{2}}{b^{2} + c^{2} + b c}

△ A B C

\frac{a}{b^{2} - c^{2}} + \frac{c}{b^{2} - a^{2}} = 0

B

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