CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

If a+b+c=0 then (a3+b3+c3) is
(a) 0 (b) abc (c) 2abc (d) 3abc

Open in App
Solution

ANSWER:
(d) 3abc
a+b+c=0⇒a+b=-c
(a+b)3=c3
a3+b3+3ab(a+b)=c3
a3+b3+3ab(c)=c3

a3+b3+c3=3abc


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon