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Byju's Answer
Standard VIII
Mathematics
Expansion of (x^2 - y^2)
If a+b+c=0, t...
Question
If a+b+c=0,then find the value of a²/bc +b²/ac +c²/ab.
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Solution
Given,
a+b+c=0
we know that,
if a+b+c=0, then a³+b³+c³=3abc
Now,
(a²/bc)+(b²/ac)+(c²/ab)=(a³+b³+c³)/abc
= 3abc/abc
=3
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