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Question

If a+b+c=0,then find the value of a²/bc +b²/ac +c²/ab.

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Solution

Given,
a+b+c=0
we know that,
if a+b+c=0, then a³+b³+c³=3abc
Now,
(a²/bc)+(b²/ac)+(c²/ab)=(a³+b³+c³)/abc
= 3abc/abc
=3

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