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Question

If a+b+c=0 then find value of a2bc+b2ac+c2ab

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Solution

We have

(a3+b3+c33abc)=(a+b+c)×(a2+b2+c2abbcac)

When a+b+c=0 [Given]

then, a3+b3+c3=3abc

a3abc+b3abc+c3abc=3 [On dividing abc both sides]

a2bc+b2ac+c2ab=3.


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