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Question

If a+b+c=0, then prove that a2bc+b2ca+c2ab=

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Solution

a2bc+b2ac+c2ab=a3+b3+c3abc
if (a+b+c)=0
a3+b3+c3=3abc
a2bc+b2ac+c2ab=3

1119521_516720_ans_92a0c5f6a7654f0ba8561101f7195a94.jpg

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