If a+b+c=0, then the roots of the equation4ax2+3bx+2c=0 are
Equal
Imaginary
Real
Noneofthese
Explanation for correct answer:
Given, a+b+c=0 and 4ax2+3bx+2c=0
For root to be define of quadratic equation then root is given by
x=-B+-D2,whereD=B2-4BACinthisgivenequation,B=-3b,A=4a,C=2
D=9b2–4(4a)(2c)=9(a+c)2–32ac=9(a–c)2+4ac>0rootsarereal
Hence the correct option is (C)
If a,b,cϵ R and 1 is a root of the equation ax2 + bx + c = 0 then the equation 4 ax2+ 3 bx + 2c = 0, c ≠ 0 has roots which are :