if a+b+c=1,ab+bc+ca=2,and abc=3 then find 1/a+bc+1/b+ca+1/c+ab

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Q. If

a, b, c

are real numbers such that

\frac{a b}{a + b} = \frac{1}{3}, \frac{b c}{b + c} = \frac{1}{4}

and

\frac{c a}{c + a} = \frac{1}{5}

, then the value of

\frac{a b c}{a b + b c + c a}

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a b + b c + c a = 0

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Q. If

a b + b c + c a = 0

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If ab+bc+ac=0, find the value of (1/a^2-bc)+(1/b^2-ca)+(1/c^2-ab)

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