If a + b + c = 16 and a2 + b2 + c2 = 90, then find the value of a3 + b3 + c3 – 3abc.

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a + b + c = 12

a^{2} + b^{2} + c^{2} = 90

a^{3} + b^{3} + c^{2} - 3 a b c

a + b + C = 12

a^{2} + b^{2} + c^{2} = 50

a b + b c + a c

a^{3} + b^{3} + c^{3} - 3 a b c

a^{3} + b^{3} + c^{3} = 3 a b c

a + b + c = 0

\frac{{(b + c)}^{2}}{3 b c} + \frac{{(c + a)}^{2}}{3 a c} + \frac{{(a + b)}^{2}}{3 a b}

If a+b+c =9 and a² + b²+ c²=35 find the value of a³ + b³ + c³ - 3ab

\frac{a^{3} + b^{3} + c^{3} - 3 a b c}{a^{2} + b^{2} + c^{2} - a b - b c - c a}

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