If a + b + c = 5
4a + 2b + c = 11
9a + 3b + c = 19
Find the value of a×b×c.
a + b + c = 5 -------------------(1)
4a + 2b + c = 11 ----------------(2)
9a + 3b + c = 19 -----------------(3)
Multiplying 4 in equation 1 and subtract it from equation 2
-2b - 3c = 9
2b + 3c = 9-----------(4)
Multiplying 9 in equation 1 and subtract equation 3 from it
6b + 3c = 26-----------(5)
Solving equation 4 and 5
We get, b=3, c=1
Substituting b and c in equation 1
We get, a + b + c = 5, a + 3 + 1 = 5
a = 1
a×b×c=1×3×1=3