If a+b+c=5 and ab+bc+ca=10 then prove that a^3+b^3+c^3-3abc=-25

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a + b + c = 5

a b + b c + c a = 10

a^{3} + b^{3} + c^{3} - 3 a b c = - 25

a^{3} + b^{3} + c^{3} - 3 a b c = - 25

a + b + c = 5

a b + b c + c a = 10

a^{3} + b^{3} + c^{3} - 3 a b c = - 25

a + b + c = 5

a b + b c + c a = 10

a^{3} + b^{3} + c^{3} - 3 a b c

a + b + c = 5

a b + b c + c a = 10

a^{3} + b^{3} + c^{3} - 3 a b c

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