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Question

If a + b + c = 9 and ab + bc + ca =23, then a3 + b3 + c3 − 3abc =

(a) 108

(b) 207

(c) 669

(d) 729

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Solution

We have to find the value of

Given

Using identity we get,

By transposing +46 to left hand side we get,

Using identity

The value of is

Hence the correct choice is .


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