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Properties of Multiplication of Integers

If a+b+c=9 an...

Question

If a + b + c = 9 and ab + bc + ca =23, then a³+ b³+ c³ − 3abc =

(a) 108

(b) 207

(c) 669

(d) 729

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Solution

We have to find the value of

Given

Using identity we get,

By transposing +46 to left hand side we get,

Using identity

The value of is

Hence the correct choice is .

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Similar questions

If a + b + c = 9 and ab + bc + ca = 23, then $a^{3} + b^{3} + c^{3} - 3 a b c =$

a + b + c = 9

a b + b c + c a = 23

, then the value of

a^{3} + b^{3} + c^{3} - 3 a b c

a + b + c

a b + b c + c a = 26

, then the value of

a^{3} + b^{3} + c^{3} - 3 a b c

a + b + c = 9

ab + bc + ca = 26,

a^{3} + b^{3} + c^{3} - 3abc

Q. If x + y + z = 9 and xy + yz + zx = 23, then the value of (x³ + y³ + z³ − 3xyz) = ?
(a) 108
(b) 207
(c) 669
(d) 729

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