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Question

If a+b+c=9 (where a, h, c are real numbers), then the minimum value of a2+b2+c2 is

A
100
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B
9
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C
27
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D
81
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Solution

The correct option is C 27

Let us First test a²+b² for say, a+b=8

Values of a & b may be taken (8,0), (7,1), (6,2), (5,3), (4,4), (3,5), (2,6), (1,7), (0,8)

As the difference between a and b decreases values of a²+b² becomes 64, 50, 40, 34, 32,( 34, 40, 50, 64).

It gives us an idea that when the difference between a and b decreases, a²+b² also decreases.

and

When a=b, a²+b² is minimum = 32.

So now we can guess that when a= b=c =3, a²+b²+c²=27 (minimum).


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