If a,b,c , all distinct are such that a,b, and c are in AP and b-a , c-b and a are in GP then a:b:c =?

2:3:4

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1:2:4

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1:3:4

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1:2:3

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4:6:7

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Solution

The correct option is D 1:2:3
Answer=d

Going from answer options is the best choice.

**Observe that only options a andd are in an AP.

By Assumption technique; taking a=2, b=3 and c=4

b-a=1, c-b=1 and a=2, which does not form a GP. Hence this option can never be true

Taking a=1, b=2 and c=3.

b-a=1, c-b=1 and a=1 is in a GP. Hence, answer option (d) is the right one

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