If A - B - C and A - B -2 then tan A - tan B - 2tan C-

∵ A + B =π2⇒tan Atan B = 1 and tan C = tan(A B) =tan A tan B1+ tan Atan B ⇒ 2tan C = tan A tan B ...

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Principal Solution of Trigonometric Equation

If A - B = ...

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If $A - B = C$ and $A + B = \frac{π}{2}$ then $tan A = tan B + 2 tan C$ .

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A + B + C = π

tan \frac{A}{2} tan \frac{B}{2} + tan \frac{B}{2} tan \frac{C}{2} + tan \frac{C}{2} tan \frac{A}{2} = 1

If $A + B + C = π$ then, $tan \frac{A}{2} \cdot tan \frac{B}{2} + tan \frac{B}{2} \cdot tan \frac{C}{2} + tan \frac{C}{2} \cdot tan \frac{A}{2}$ =

A + B + C = π

\frac{tan A + tan B + tan C}{tan A tan B tan C} =

x = tan (\frac{B - C}{2}) tan \frac{A}{2}, y = tan (\frac{C - A}{2}) tan \frac{B}{2}, z = tan (\frac{A - B}{2}) tan \frac{C}{2}

x + y + z = ?

Δ A B C

tan \frac{A}{2} tan \frac{B}{2} + tan \frac{B}{2} tan \frac{C}{2} = \frac{2}{3}

a + c ?

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