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Question

If a, b, c and d are consecutive multiples of 5 and a<b<c<d, find the value of (ac)(db).

A
100
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B
100
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C
25
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D
25
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Solution

The correct option is A 100
Given a,b,c,d are consecutive multiple of 5 i.e. a,b,c,d forms an AP with common difference 5
b=a+5,c=a+10,d=a+15
Also, a<b<c<dac<0 and db>0
(ac)(db)=(10)(10)=100

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