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Question

If a,b,c and d are real numbers such that a2+b2+c2+d2=1 and if A=[a+ibc+idc+idaib],where i2=1, then A1=

A
[a+ibcidcidaib]
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B
[aibc+idc+ida+ib]
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C
[aibcidcida+ib]
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D
[a+ibc+idcidaib]
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Solution

The correct option is C [aibcidcida+ib]
A=[a+ibc+idc+idaib]
A1=Adj A|A|
Adj A=[aibcidcida+ib]
|A|=a2+b2+c2+d2=1
A1=[aibcidcida+ib]

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