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Question

If A,B,C are acute positive angles such that A+B+C=π and cotAcotBcotC=k, then

A
k<19
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B
k>13
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C
k133
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D
k133
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Solution

The correct option is C k133
A+B+C=πtanA+tanB+tanC=tanAtanBtanC

Now, A.M.G.M.
tanA+tanB+tanC3(tanAtanBtanC)13tanAtanBtanC3(tanAtanBtanC)13(tanAtanBtanC)233(1k)233k133

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