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Question

If A,B,C are acute positive angles such that A+B+C=π and cotAcotBcotC=k, then

A
k133
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B
k>13
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C
k133
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D
k<19
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Solution

The correct option is A k133
A+B+C=π and 0<A,B,C<π2, using A.M. G.M. cotA+cotB+cotC3k1/3
cotAcotBcotC=k133 (the minimum value of A.M. is G.M. and in this case A=B=C=π3)

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