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Question

If a, b, c are all nonzero and a + b + c = 0, prove that a2bc+b2ca+c2ab=3.

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Solution

a+b+c=0a3+b3+c3=3abc

Thus, we have:
a2bc+b2ca+c2ab=a3+b3+c3abc
=3abcabc=3

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