If a,b,c are distinct positive real numbers such that b(a+c) = 2ac then the roots ax2 + 2bx + c = 0 are :
Real and equal
Real and distinct
Imaginary
None of these
D= 4b2 -4ac = 4{ 4a2c2(a+c)2 -ac}
=4ac(a+c)2 {4ac-(a+c)2 }
= −4ac(a+c)2 *(a−c)2 <0 [ since a,c>0]
=> roots are imaginary
If a, b, c are distinct positive real numbers such that b(a + c) = 2ac then the roots of ax2+bx+c=0 are