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Question

If a,b,c are distinct positive real numbers such that b(a+c) = 2ac then the roots ax2 + 2bx + c = 0 are :


A

Real and equal

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B

Real and distinct

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C

Imaginary

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D

None of these

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Solution

The correct option is C

Imaginary


D= 4b2 -4ac = 4{ 4a2c2(a+c)2 -ac}

=4ac(a+c)2 {4ac-(a+c)2 }

= 4ac(a+c)2 *(ac)2 <0 [ since a,c>0]

=> roots are imaginary


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