Question

If $a,b,c$ are in $A.P.$ and $a^2,b^2,c^2$ are in $G.P.$ such that $a<b<c$ and $a+b+c=\frac{3}{4}$ then the value

• A. $\frac{1}{4}-\frac{1}{\sqrt{2}}$
• B. $\frac{1}{4}-\frac{1}{3\sqrt{2}}$
• C. $\frac{1}{4}-\frac{1}{4\sqrt{2}}$
• D. $\frac{1}{4}-\frac{1}{2\sqrt{2}}$

Answer 1

The correct option is D $\frac{1}{4}-\frac{1}{2\sqrt{2}}$

If a,b,ca,b,c are in A.P.A.P. and a2,b2,c2a2,b2,c2 are in G.P.G.P. such that a<b<ca<b<c and a+b+c=34a+b+c=34 then the value

The correct option is D