If a, b, c are in A.P. then 3a, 3b, 3c are in
Let the A.P. be a, a+d, a+2d
⇒ The sequence is 3a, 3a+d, 3a+2d ≡ 3a, 3a × 3d, 3a × (3d)2
⇒ It is a G.P. with common ratio 3d and first term is 3a.
If a, b, c are in A.P. then 3a, 3b, 3c are in ___.
If a,b,c are in A.P., then 3a,3b,3c are in G.P..
If a,b,c are in AP then show that 3a , 3b , 3c are in GP