If a,b,c are in A.P., then abc,1c,2b are in
A.P
G.P
H.P
None of these
a,b,c be in A.P. the divided each term by bc, we get
abc,1c,1b be in A.P. But it is 2b in place of 1b, so answer is (d).
If 1b−a+1b−c=1a+1c, then a,b,c, are in
If the roots of a(b−c)x2+b(c−a)x+c(a−b) = 0 be equal then a,b,c are in
if a,b,c ϵ R,a,b,c ≠ 0, ∑ a2 = ∑ab, then a,b,c are in