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Question

If a, b, c are in A.P., then the determinant

x+2x+3x+2ax+3x+4x+2bx+4x+5x+2c

(a) 0
(b) 1
(c) x
(d) 2x

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Solution

(a) 0


x + 2 x + 3 x + 2ax + 3 x + 4 x + 2bx + 4 x + 5 x + 2c= 0 0 2a + c - 2bx + 3 x + 4 x + 2bx + 4 x + 5 x + 2c Applying R1R1+R3-R2, R1R1 - R2 = 0 0 0x+3 x+4 x+2bx+4 x+5 x+2c a, b, c are in A.P.= 0

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