If a, b, c are in AP and a + b + c = 5, Find the value of 3b
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a, b, c are in AP
⇒ (a+c)2 = b
⇒ a + c = 2b
a + b + c =5 (given)
b + (a + c) = 5
b + 2b = 5
3b = 5
b = 53
⇒ 3b = 5
If 2160=2a.3b.5c, find a, b and c. Hence calculate the value of 3a×2−b×5−c
If a + b+ c = 5 , 3a + 2b + c = 7, 9a + 3b + c = 13 Find the value of a, b and c.