If a,b,c are in AP then,a×b,b2,c×b are also in AP.
True
Given that a,b,c are in AP.
When each term of an AP is multiplied by a constant number, then the resulting sequence is also in an AP by the property of AP.
Here, all the three terms in the AP is multiplied by a constant 'b'.
Therefore, the resulting sequence is also an AP.