If a, b, c are in AP then, a×b,b2,c×b are also in AP?
True
It is given that a, b, c are in AP.
Now by the property of AP's we know that when each term of an AP is multiplied by a constant number,
then the resulting sequence is also in an AP. In the given case, b is multiplied to all the terms of the AP.
So, the resultant sequence is an AP with common difference b x d, where d is the common difference of the previous AP.