If a- b- c are in AP then a-bc- 1-c- 1-b are in

The correct option is A APGiven a,b,c are in APDividing by bc a/bc, 1/c, 1/b are in AP #160; ( a,b,c gt;0 ) ...

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If $a, b, c$ are in AP then $\frac{a}{b c}$ , $\frac{1}{c}$ , $\frac{1}{b}$ are in

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none of these

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If $a, b, c$ are in AP; then $\frac{1}{b c}, \frac{1}{c a} a n d \frac{1}{a b}$ are in AP.

a + \frac{1}{b c}

b + \frac{1}{c a}

c + \frac{1}{a b}

\frac{a}{b c}, \frac{1}{c}, \frac{2}{b}

If $a, b, c$ are in AP; then $\frac{1}{b c}, \frac{1}{c a} a n d \frac{1}{a b}$ are in AP.

\frac{1}{\sqrt{b} + \sqrt{c}}, \frac{1}{\sqrt{c} + \sqrt{a}}, \frac{1}{\sqrt{a} + \sqrt{b}}

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