Question

If $a,b,c$ are in continued proportion, then $\frac{a}{a+2b}=\frac{a-2b}{a-4c}$

• A. True
• B. False

Answer 1

The correct option is A True

Given,

$\frac{a}{a+2b}=\frac{a-2b}{a-4c}$

$a(a-4c)=(a+2b)(a-2b)$

$a^2-4ac=a^2-4b^2$

$4b^2-4ac=0$

$b^2=ac$

Therefore $a,b,c$ are in continued proportion.