If a, b, c are in H.P., then ab+c,bc+a,ca+b are in
A
A.P.
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B
H.P.
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C
G.P.
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D
None of these
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Solution
The correct option is B H.P. Given a,b,cϵH.P. So, 1a,1b,1cϵA.P. a+b+ca,b+c+ab,c+a+bcϵA.P. By using concept if a,b,cϵA.P. Then their reciprocals are in H.P.