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Question

If a,b,c are non negative real numbers and ∣ ∣ ∣(a2+x2)abacab(b2+x2)bcacbc(c2+x2)∣ ∣ ∣ is divisible by xn, where nN, then the maximum possible value of n is

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Solution

Let A=∣ ∣ ∣(a2+x2)abacab(b2+x2)bcacbc(c2+x2)∣ ∣ ∣
Using row operations, we get
R1aR1,R2bR2, R3cR3A=1abc∣ ∣ ∣a(a2+x2)a2ba2cab2b(b2+x2)b2cac2bc2c(c2+x2)∣ ∣ ∣A=∣ ∣ ∣(a2+x2)a2a2b2(b2+x2)b2c2c2(c2+x2)∣ ∣ ∣

R1R1+R2+R3A=(a2+b2+c2+x2)∣ ∣ ∣111b2b2+x2b2c2c2(c2+x2)∣ ∣ ∣

C2C2C1, C3C3C1A=(a2+b2+c2+x2)∣ ∣ ∣100b2x20c20x2∣ ∣ ∣A=x4(a2+b2+c2+x2)

Hence, the maximum value of n=4

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