If a, b, c are position vectors of the vertices of a ΔABC, then −−→AB+−−→BC+−−→CA=
A
0
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B
2a
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C
2b
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D
3c
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Solution
The correct option is A 0 If we join head to tail all the vectors, then we end up at the initial point where we started, that is vertice A. Hence the net sum is 0.