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Question

If a,b,c are positive real numbers in geometric progression, then the graph of y=ax2+bx+c is a curve that

A
Intersects the x-axis at two points
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B
Is entirely below the x-axis
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C
Is entirely above the x-axis
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D
Is tangent to the x-axis
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Solution

The correct option is C Is entirely above the x-axis
Let

a=a,b=ar,c=ar2

Then

y=ax2+arx+ar2

Discriminant D=a2r24a2r2=3a2r2

Hence as D is negative y has complex roots and the graph lies above the x-axis entirely since coeffiecient of x2 is positive

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