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Question

If a,b,c are real distinct numbers satisfying the condition a+b+c=0, then the roots of the quadratic equation 3ax2+5bx+7c=0 are

A
positive
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B
negative
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C
real and distinct
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D
imaginary
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Solution

The correct option is C real and distinct
Given equation is : 3ax2+5bx+7c=0
Also given is that a+b+c=0(1)
Discriminant of the equation D=b24ac

=(5b)24(3a)(7c)

=25b284ac(2)
Substituting the value of b from equation (1) in equation (2),we get
D =25(ac)284ac

=25(a+c)284ac

=25a2+25c234ac

=4a2+4c2+8ac + 21a2+21c242ac

=4(a+c)2+21(ac)2>0
Since D>0,both the roots will be real and distinct.

Also,in the absence of information on the coefficients a,b and c in the equation we can't conclude whether both the roots will be positive or negative.
Hence,option (C) is the correct alternative.

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