If a,b,c are real distinct numbers satisfying the condition a+b+c=0, then the roots of the quadratic equation 3ax2+5bx+7c=0 are
A
positive
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B
negative
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C
real and distinct
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D
imaginary
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Solution
The correct option is C real and distinct Given equation is : 3ax2+5bx+7c=0 Also given is that a+b+c=0…(1) Discriminant of the equation ⇒D=b2−4ac
=(5b)2−4(3a)(7c)
=25b2−84ac…(2)
Substituting the value of b from equation (1) in equation (2),we get
D =25(−a−c)2−84ac
=25(a+c)2−84ac
=25a2+25c2−34ac
=4a2+4c2+8ac + 21a2+21c2−42ac
=4(a+c)2+21(a−c)2>0 Since D>0,both the roots will be real and distinct.
Also,in the absence of information on the coefficients a,b and c in the equation we can't conclude whether both the roots will be positive or negative.