If a, b, c are real numbers such that $a^{2} + b^{2} + c^{2} = 1$ then $a b + b c + c a > - \frac{1}{2}$

True

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False

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Solution

The correct option is A True
True
$(a + b + c)^{2} > 0$
$∴ \sum a^{2} + 2 \sum a b > 0$ or $\sum a b > - \frac{1}{2}$ .

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